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Answer :
Given :
Radius of the base = \(\frac{28}{2} cm = 14 cm\)
Also, Volume of a right circular cone = 9856 \({cm}^3\)
i) Let the height of the cone be h.
But, we know that,
Volume of right circular cone = \(\frac{1}{3} {\pi} {r}^2 h\)
\(\Rightarrow \) 9856 \({cm}^3\) = \(\frac{1}{3} × \frac{22}{7} × {14}^2 × h\) \({cm}^2\)
\(\Rightarrow \) h = 48 cm.
Therefore, height of the cone is 48 cm.
ii)We know, slant height of cone
= \(\sqrt({h}^2 + {r}^2)\) cm
= \(\sqrt({48}^2 + {14}^2)\) cm
l = \(50 cm\)
Therefore, slant height of the cone is 50 cm.
iii) We also know that,
Curved surface area of the cone
= \({\pi}rl\)
= \(\frac{22}{7} × 14 × 50 {cm}^2\)
= 2200 \({cm}^2\)
Therefore, the curved surface area of the cone is 2200 \({cm}^2\).