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A random survey of the number of children of various age groups playing in a park was
found as follows :
| Age (in years) | No. of children (frequency) |
| 1 - 2 | 5 |
| 2 - 3 | 3 |
| 3 - 5 | 6 |
| 5 - 7 | 12 |
| 7 - 10 | 9 |
| 10 - 15 | 10 |
| 15 - 17 | 4 |
Draw a histogram to represent the data above.
Answer :
Here, it can be observed that the data has class intervals of varying width. The
proportion Of children per 1 year interval can be calculated as follows.
| Age (in years) | No. of children (frequency) | Width of class | Length of rectangle |
| 1 - 2 | 5 | 1 | \(\frac{5 × 1}{1} = 5\) |
| 2 - 3 | 3 | 1 | \(\frac{3 × 1}{1} = 3\) |
| 3 - 5 | 6 | 2 | \(\frac{6 × 1}{2} = 3\) |
| 5 - 7 | 12 | 2 | \(\frac{12 × 1}{2} = 6\) |
| 7 - 10 | 9 | 3 | \(\frac{9 × 1}{3} = 3\) |
| 10 - 15 | 10 | 5 | \(\frac{10 × 1}{5} = 2\) |
| 15 - 17 | 4 | 2 | \(\frac{4 × 1}{2} = 2\) |
Taking the age of children on x-axis and proportion children per 1 year interval on y-axis, the histogram can be drawn as follows.
