The length of the minute hand of a clock is 14 cm. Find the area swept by the minute hand in 5 minutes.

$$= \ ( \frac{ \theta}{360} \ × \ \pi r^2 \ × \ 5) \$$
$$= \ \frac{6}{360} \ × \ \frac{22}{7} \ × \ (14)^2 \ × \ 5$$
$$= \ \frac{1}{60} \ × \ \frac{22}{7} \ × \ 196 \ × \ 5 \$$
$$= \ \frac{154}{3} \ cm^2$$