Premium Online Home Tutors
3 Tutor System
Starting just at 265/hour
Answer :
Here, 8 cm is the radius of the quadrants ABMD and BNDC.
Sum of their areas
\( = \ 2 \ × \ \frac{1}{4} \pi r^2 \ = \ \frac{1}{2} \pi r^2 \)
\( = \frac{1}{2} \ × \ \frac{22}{7} \ × \ 64 \ = \ \frac{704}{7} \) cm2
Area of the square ABCD
\( = \ 8 \ × \ 8 \ = \ 64 \) cm2
Thus, Area of the shaded region = Sum of the area of quadrants - Area of the square ABCD
\( = \frac{704}{7} \ - \ 64 \ = \ \frac{704 \ - \ 448}{7} \)
\( = \ \frac{256}{7} \) cm2