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Answer :
Volume of the sphere \( = \ \frac{4}{3} \pi r^3 \ = \ \frac{4}{3} \ × \ \pi \ × \ (4.2)^3 \) cm3
If h is the height of a cylinder of radius 6 cm. Then its volume \(= \ \pi (6)^2 h \ = \ 36\pi h \) cm3
\(\therefore \) The volume of metal in the form of sphere and cylinder remains the same , we have
\(\Rightarrow 36 \pi h \ = \ \frac{4}{3} \ × \ \pi \ × \ (4.2)^3 \)
\(\Rightarrow \ h \ = \ \frac{1}{36} \ × \ \frac{4}{3} \ × \ (4.2)^3 \)
\( \Rightarrow \ h \ = \ 2.744 \) cm