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Answer :
(i) Solving it using long division:
\(\begin{array}{rrrr|ll} x^3 & - 3x^2 & + 5x & - 3 & x^2 - 2\\ -x^3 & & + 2x & & x - 3 \\
\hline & -3x^2 & +7x & -3\\ & \phantom{-}3x^2 & & -6 & & & & \\ \hline & & +7x & -9 \\ \hline \end{array}\)
Here, Quotient = \(x - 3\) and Remainder = \(7x - 9\).
(ii) Solving it using long division:
\(\begin{array}{rrrr|ll} x^4 & - 3x^2 & + 4x & + 5 & x^2 - x + 1\\ x^3 -x^4 & -x^2 & & & x^2 + x - 3 \\
\hline x^3 & - 4x^2 & + 4x & + 5\\ \phantom{-}x^3 & + x^2 & -x & & & \\ \hline & -3x^2 & + 3x & +5 \\ & +3x^2 & -3x & +3 \\ \hline & & & 8 \\ \hline \end{array}\)
Here, Quotient = \(x^2 + x - 3\) and Remainder = \( 8\).
(iii) Solving it using long division:
\(\begin{array}{rrrr|ll} &x^4 & - 5x &+ 6 &-x^2 + 2\\ &2x^2 - x^4 & & & -x^2 - 2 \\
\hline & 2x^2 & - 5x & + 6\\ & \phantom{-}-2x^2 & & + 4 & & & & \\ \hline & & -5x &+10 \\ \hline \end{array}\)
Here, Quotient = \(-x^2 - 2\) and Remainder = \(-5x + 10\).