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Answer :
As the image is real , so the magnification(m) must be real.
\( m= \frac{h^`}h=\frac{-v}u = -3 or v=3u\)
\( u =-10cm \)
therefore, \( m= \frac{-v}u \)
\( -3= \frac{-v}{-10} \)
\( v= -30cm \)