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Answer :
Resistance of electric lamp, \(R_1 = 100 \Omega \)
Resistance of toaster, \(R_2 = 50 \Omega \)
Resistance of water filter, \(R_3 = 500 \Omega \)
Equivalent resistance R of the three appliances connected in parallel, is:
\(\frac{1}R=\frac{1}{R_1} +\frac{1}{R_2}+\frac{1}{R_3} \)
\(\frac{1}R= \frac{1}{100} +\frac{1}{50}+\frac{1}{500}=\frac{16}{500}\)
\(R=\frac{500}{16} \Omega =31.25 \Omega \)
Resistance of electric iron = Equivalent resistance of the three appliances connected in parallel = 31.25 \(\Omega \)
Applied voltage, V = 220 V
So,current\(I=\frac{v}R =\frac{220}{31.25}=7.04A \)