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1.Find :
i)\(64^{1/2}\)
ii)\(32^{1/5}\)
iii)\(125^{1/3}\)

Answer :

i) \(64^{1/2}\) = \((8 × 8)^{1/2}\) = \(8^{1/2 × 2}\) =\( 8\)

ii) \({32}^{1/5}\) = \((2 × 2 × 2 × 2 × 2)^{1/5}\) = \(2^{1/5 × 5}\) =\( 2\)

iii) \({125}^{1/3}\) = \((5 × 5 × 5)^{1/3}\) = \(5^{3 × 1/3}\) = \(5\)