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# Draw a line segment AB of length 8 cm. Taking A as centre, draw a circle of radius 4 cm and taking B as centre, draw another circle of radius 3 cm. Construct tangents to each circle from the centre of the other circle.

Steps to construct the required figure:
Step 1: Draw a line segment AB of 8 cm.

Step 2. Taking A as centre , draw a circle of radius 4 cm and taking B as centre, draw a circle of radius 3 cm.

Step 3. With M as centre which is the center of line AB, draw a circle of radius MA or MB, intersecting circle with centre B at R and S, circle with center as A at P and Q.

Step 4. Join AR,AS, BP and BQ and hence we got the required tangents.

JUSTIFICATION:

On joining BP, we get $$\angle$$ BPA=90° ; [$$\therefore$$ BPA is the angle in the semi-circle]

Therefore, AP $$\perp$$ BP

So,AP is the tangent to the circle because BP is the radius of the given circle.

Similarly, AR,BQ and AS are the tangents.