8.Is $$\frac{8}9$$ the multiplicative inverse of $$-1\frac{1}8$$? Why or why not?
We have $$-1\frac{1}8=\frac{-9}{8}$$
Since multiplication inverse of $$\frac{8}9 is \frac{9}8$$ but not $$\frac{-9}8$$
Because, $$\frac { 8 }{ 9 } \times -1\frac { 1 }{ 8 } =\frac { 8 }{ 9 } \times \frac { -9 }{ 8 } =-1\neq 1$$
So, $$\frac{8}9$$ is not the multiplicative inverse of $$-1\frac{1}8$$.