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Answer :
Let the three consecutive multiples of 8 be 8x, 8x + 8 and 8x + 16.
As per the given conditions in the question we have,
8x+8x+8+8x+16=888,
\(\Rightarrow\)24x+24=888
\(\Rightarrow\)24x+24-24=888-24[subtracting 24 from both the sides]
\(\Rightarrow\)24x=864
\(\Rightarrow\)24x÷24=864÷24[dividing both the sides by 24 ]
\(\Rightarrow\) x= 36
So we have the consecutive numbers as :
8x=8×36=288
8x+8=8×36+8=294
8x+16=8×36+16=304
Thus, we have the required numbers as 288,294 and 304.