7.The sum of three consecutive multiples of 8 is 888. Find the multiples.

Let the three consecutive multiples of 8 be 8x, 8x + 8 and 8x + 16.
As per the given conditions in the question we have,

8x+8x+8+8x+16=888,

\(\Rightarrow\)24x+24=888

\(\Rightarrow\)24x+24-24=888-24[subtracting 24 from both the sides]

\(\Rightarrow\)24x=864

\(\Rightarrow\)24x÷24=864÷24[dividing both the sides by 24 ]

\(\Rightarrow\) x= 36

So we have the consecutive numbers as :

8x=8×36=288

8x+8=8×36+8=294

8x+16=8×36+16=304
Thus, we have the required numbers as 288,294 and 304.