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# 9. 3(5z – 7) – 2(9z – 11) = 4(8z – 13) – 17

Given that, 3(5z – 7) – 2(9z – 11) = 4(8z – 13) – 17

$$\Rightarrow$$15z – 21 – 18z + 22 = 32z – 52 – 17 [Solving the bracket]

$$\Rightarrow$$ -3z + 1 = 32z – 69

$$\Rightarrow$$ -3z – 32z = – 69 – 1 [Transposing 32z to LHS and 1 to RHS]

$$\Rightarrow$$ -35z = -70

$$\Rightarrow$$ z = 2

Thus, z = 2 is the required solution.