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9. 3(5z – 7) – 2(9z – 11) = 4(8z – 13) – 17


Answer :

Given that, 3(5z – 7) – 2(9z – 11) = 4(8z – 13) – 17

\(\Rightarrow\)15z – 21 – 18z + 22 = 32z – 52 – 17 [Solving the bracket]

\(\Rightarrow\) -3z + 1 = 32z – 69

\(\Rightarrow\) -3z – 32z = – 69 – 1 [Transposing 32z to LHS and 1 to RHS]

\(\Rightarrow\) -35z = -70

\(\Rightarrow\) z = 2

Thus, z = 2 is the required solution.

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