5. \(\frac { 7y+4 }{ y+2 } =\frac { -4 }{ 3 }\)

Given that, \(\frac { 7y+4 }{ y+2 } =\frac { -4 }{ 3 }\)

\(\Rightarrow 3(7y + 4) = -4 (y + 2)\quad \) [Cross-multiplication]

\(\Rightarrow 21y + 12 = -4y – 8\quad \) [Solving the bracket]

\(\Rightarrow 21y + 4y = -12 – 8\quad \) [Transposing 4y to LHS and 12 to RHS]

\(\Rightarrow 25y = -20\quad\) [Transposing 25 to RHS]

\(\Rightarrow y = \frac { -4 }{ 5 }\)