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Answer :
(i) For ∠D + ∠B = \(180^{\circ}\), quadrilateral ABCD may be a parallelogram if
the sum of measures of adjacent angles is \(180^{\circ}\) and also the opposite angles should be of same measures. So here, ABCD can be but need not be a parallelogram.
(ii) Given: AB = DC = 8 cm, AD = 4 cm, BC = 4.4 cm
In general the opposite sides od a parallelogram is equal.
But here, \(AD \neq BC\)
Thus, ABCD cannot be a parallelogram.
(iii) \(∠A = 70^{\circ} and ∠C = 65^{\circ}\)
Since \(∠A \neq ∠C\quad \)[Opposite angles of quadrilateral are not equal.]
Hence, ABCD is not a parallelogram.