# 4.Observe the following pattern and find the missing digits. $$11^2$$ = 121 $$101^2$$ = 10201 $$1001^2$$ = 1002001 $$100001^2$$ = 1…2…1 $$10000001^2$$ = ………

According to the above pattern, we can observe that the squares of the given numbers have the same number of zeroes before and after the digit 2.Therefore, we have
$$100001^2$$ = 10000200001

$$10000001^2$$ = 100000020000001