4.Observe the following pattern and find the missing digits.
\(11^2\) = 121

\(101^2\) = 10201

\(1001^2\) = 1002001

\(100001^2\) = 1…2…1

\(10000001^2\) = ………

According to the above pattern, we can observe that the squares of the given numbers have the same number of zeroes before and after the digit 2.Therefore, we have
\(100001^2\) = 10000200001

\(10000001^2\) = 100000020000001