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Answer :
We know that if n is number of digits in a perfect square number, then it's square root will have \(\frac{n}2\) digits if n is even and \{\frac{(n+1)}2\) digits if n is odd.
(i) 64
Here n is even i.e, 2.
So, number of digits in \(\sqrt{64} = \frac { 2 }{ 2 } = 1\)
(ii) 144
Here n is odd i.e, 3.
So, number of digits in square root = \(\frac { 3+1 }{ 2 } = 2\)
(iii) 4489
Here n is even i.e, 4.
Number of digits in square root =\( \frac { 4 }{ 2 } = 2\)
(iv) 27225
Here n is odd i.e, 5.
Number of digits in square root =\( \frac { 5+1 }{ 2 } = 3\)
(iv) 390625
Here n is even i.e, 6.
So, number of digits in square root =\( \frac { 6 }{ 2 } = 3\)