3 Tutor System
Starting just at 265/hour

# 3.Find the square root of the following decimal numbers. (i) 2.56 (ii) 7.29 (iii) 51.84 (iv) 42.25 (v) 31.36

(i)
$$\qquad \begin{array}{c|lcr} &1.6\\ \hline 1 &\;\; \;\bar{2.}\bar{56}\\ &-1\\ \hline 26 &\;\;\; 156\\ &\;\;\; 156\\ \hline &\;\;\;\;\; 0\\ \hline \end{array}$$

Hence we have, $$\sqrt{2.56}=1.6$$

(ii)
$$\qquad \begin{array}{c|lcr} &2.7\\ \hline 2 &\;\; \;\bar{7.}\bar{29}\\ &-4\\ \hline 47 &\;\;\; 329\\ &\;\;\; 329\\ \hline &\;\;\;\;\; 0\\ \hline \end{array}$$

Hence we have, $$\sqrt{7.29}=2.7$$

(iii)
$$\qquad \begin{array}{c|lcr} &7.2\\ \hline 7 &\;\; \;\bar{51.}\bar{84}\\ &-49\\ \hline 142 &\;\;\; 284\\ &\;\;\; 284\\ \hline &\;\;\;\;\; 0\\ \hline \end{array}$$

Hence we have, $$\sqrt{51.84}=7.2$$

(iv)
$$\qquad \begin{array}{c|lcr} &6.5\\ \hline 6 &\;\; \;\bar{42.}\bar{25}\\ &-36\\ \hline 125 &\;\;\; 625\\ &\;\;\; 625\\ \hline &\;\;\;\;\; 0\\ \hline \end{array}$$

Hence we have, $$\sqrt{42.25}=6.5$$

(v)
$$\qquad \begin{array}{c|lcr} &5.6\\ \hline 5 &\;\; \;\bar{31.}\bar{36}\\ &-25\\ \hline 106 &\;\;\;\;\; 636\\ &\;\;\;\;\; 636\\ \hline &\;\;\;\;\; 0\\ \hline \end{array}$$

Hence we have, $$\sqrt{31.36}=5.6$$