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Answer :

We have the area of the square plot =\( side \times side = 25 m \times 25 m = 625 m^2\)

Area of the rectangular house =\( l \times b = 20 m \times 15 m = 300 m^2\)

Therefore, Area of the garden to be developed = Area of the plot – Area of the house = \(625 m^2 – 300 m^2 = 325 m^2\)

Cost of developing the garden = \(₹ 325 \times 55 = ₹ 17875\)

- 1.A square and a rectangular field with measurements as given in the figure have the same perimeter. Which field has a larger area?
- 3.The shape of a garden is rectangular in the middle and semicircular at the ends as shown in the diagram. Find the area and the perimeter of this garden. [Length of rectangle is 20 – (3.5 + 3.5) metres]
- 4.A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm. How many such tiles are required to cover a floor of area 1080 m2? (If required you can split the tiles in whatever way you want to fill up the corners).
- 5.An ant is moving around a few food pieces of different shapes scattered on the floor. For which food-piece would the ant have to take a longer round? Remember, the circumference of a circle can be obtained by using the expression C = \(2\pi r\), where r is the radius of the circle.

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