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Answer :
First term = a = 3,
Common difference = d = 8 – 3 = 13 – 8 = 5
\(a_n\) = 78
Using formula \(a_n = a + (n - 1)d\), to find \(n^{th}\) term of arithmetic progression,
\(\Rightarrow \) 78 = 3 + (n - 1) 5
\(\Rightarrow \) 75 = 5n - 5
\(\Rightarrow \) 80 = 5n
\(\Rightarrow \) n = 16
It means \(16^{th}\) term of the given AP is equal to 78.