Q.6 Angles Q and R of a APQR are 25° and 65°. Write which of the following is true.
(i) $$PQ^2 + QR^2 = RP^2$$
(ii)$$PQ^2 + RP^2 = QR^2$$
(iii)$$RP^2 + QR^2 = PQ^2$$

$$\angle P + \angle Q + \angle R = 180°$$(Angle sum property)
$$\angle$$P + 25° + 65° = 180°
$$\angle$$P + 90° = 180°
$$\angle$$P = 180° – 90° – 90°
$$\triangle$$PQR is a right triangle, right angled at P
$$\therefore PQ^2 + QR^2 \neq RP^2$$ (By Pythagoras property)
$$\therefore$$ $$PQ^2 + RP^2 = QP^2$$ (By Pythagoras property)
$$\therefore RP^2 + QR^2 \neq PQ^2$$(By Pythagoras property)