Q.3 Find the product:
(i) \(\frac{9}{2} \) × \((-\frac{7}{4} ) \)
(ii) \(\frac{9}{2} \) × (-9 )
(iii) \(\frac{-6}{5} \)× \(\frac{9}{11} \)
(iv) \(\frac{3}{7} \) × \((-\frac{2}{5} ) \)
(v) \(\frac{3}{11} \)× \(\frac{2}{5} \)
(vi) \(\frac{3}{-5} \)× \(\frac{-5}{3} \)


Answer :

(i) \(\frac{9}{2} \)× \(\frac{-7}{4} \) = \(\frac{9×-7}{2×4} \)= \(\frac{-63}{8} \) = \(-7\frac{7}{8} \)
(ii) \(\frac{9}{2} \) × (-9 )= \(\frac{-81}{2} \) =\(-40\frac{1}{2} \)
(iii) \(\frac{-6}{5} \)× \(\frac{9}{11} \) = \(\frac{-6×9}{5×11} \)= \(\frac{-54}{55} \)
(iv) \(\frac{3}{7} \) × \((-\frac{2}{5} ) \)= \(\frac{-3×2}{7×5} \) = \(\frac{-6}{35} \)
(v) \(\frac{3}{11} \)× \(\frac{2}{5} \) = \(\frac{3×2}{11×5} \)=\(\frac{6}{55} \)
(vi) \(\frac{3}{-5} \)× \(\frac{-5}{3} \) = \(\frac{3×(-5)}{-5×3} \) =\(\frac{-15}{-15} \)= 1

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