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Answer :

The smallest 3-digit number = 100

Since LCM of 6, 8, 12

$$
\begin{array}{|l}
\llap{2~~~~} 6 \\ \hline
\llap{3~~~~} 3 \\ \hline
1
\end{array}
$$
$$
\begin{array}{|l}
\llap{2~~~~} 8 \\ \hline
\llap{2~~~~} 4 \\ \hline
\llap{2~~~~} 2 \\ \hline
1
\end{array}
$$
$$
\begin{array}{|l}
\llap{2~~~~} 12 \\ \hline
\llap{2~~~~} 6 \\ \hline
\llap{3~~~~} 3 \\ \hline
1
\end{array}
$$
6= 2× 3

8 = 2× 2 × 2

12 = 2 × 2 × 3

Then LCM = 2 × 2 × 3 × 2 = 24

Now we need to find the smallest 3-digit multiple of 24

\(\therefore \) 24 × 4 = 96 and 24 × 5 = 120

Hence, 120 is the smallest 3-digit number which is exactly divisible by 6, 8 and 12

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- NCERT solutions for class 6 maths chapter 1 Knowing Our Numbers
- NCERT solutions for class 6 maths chapter 2 Whole Numbers
- NCERT solutions for class 6 maths chapter 3 Playing with Numbers
- NCERT solutions for class 6 maths chapter 4 Basic Geometrical Ideas
- NCERT solutions for class 6 maths chapter 5 Understanding Elementary Shapes
- NCERT solutions for class 6 maths chapter 6 Integers
- NCERT solutions for class 6 maths chapter 7 Fractions
- NCERT solutions for class 6 maths chapter 8 Decimals
- NCERT solutions for class 6 maths chapter 9 Data Handling
- NCERT solutions for class 6 maths chapter 10 Mensuration
- NCERT solutions for class 6 maths chapter 11 Algebra
- NCERT solutions for class 6 maths chapter 12 Ratio and Proportion
- NCERT solutions for class 6 maths chapter 13 Symmetry
- NCERT solutions for class 6 maths chapter 14 Practical Geometry

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