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(a)\(\frac{2}{3} + \frac{1}{7} \)

(b)\(\frac{3}{10} + \frac{7}{15} \)

(c) \(\frac{4}{9} + \frac{2}{7} \)

(d) \(\frac{5}{7} + \frac{1}{3} \)

(e) \(\frac{2}{5} + \frac{1}{6} \)

(f) \(\frac{4}{5} + \frac{2}{3} \)

(g) \(\frac{3}{4} - \frac{1}{3} \)

(h) \(\frac{5}{6} - \frac{1}{3} \)

(i) \(\frac{2}{3} + \frac{3}{4} + \frac{1}{2} \)

(j) \(\frac{1}{2} + \frac{1}{3} + \frac{1}{6} \)

(k) \(1\frac{1}{3} + 3\frac{2}{3} \)

(l) \(4\frac{2}{3} + 3\frac{1}{4} \)

(m) \(\frac{16}{5} - \frac{7}{5} \)

(n) \(\frac{4}{3} - \frac{1}{2} \)

Answer :

(a)\(\frac{2}{3} + \frac{1}{7} \)

LCM of 7 and 3 = 21

\(\frac{2×7}{3×7} + \frac{1×3}{7×3} \)

= \(\frac{14}{21} + \frac{3}{21} \)

= \(\frac{17}{21} \)

(b)\(\frac{3}{10} + \frac{7}{15} \)

LCM of 10 and 15 = 30

\(\frac{3×3}{10×3} + \frac{7×2}{15×2} \)

= \(\frac{9}{30} + \frac{14}{30} \)

= \(\frac{23}{30} \)

(c) \(\frac{4}{9} + \frac{2}{7} \)

LCM of 9 and 7 = 63

\(\frac{4×7}{9×7} + \frac{2×9}{7×9} \)

= \(\frac{28}{63} + \frac{18}{63} \)

= \(\frac{46}{63} \)

(d) \(\frac{5}{7} + \frac{1}{3} \)

LCM of 7 and 3 = 21

\(\frac{5×3}{7×3} + \frac{1×7}{3×7} \)

= \(\frac{15}{21} + \frac{7}{21} \)

= \(\frac{22}{21} \)

(e) \(\frac{2}{5} + \frac{1}{6} \)

LCM of 5 and 6 = 30

\(\frac{2×6}{5×6} + \frac{1×5}{6×5} \)

= \(\frac{12}{30} + \frac{5}{30} \)

= \(\frac{17}{30} \)

(f) \(\frac{4}{5} + \frac{2}{3} \)

LCM of 5 and 3 = 15

\(\frac{4×3}{5×3} + \frac{2×5}{3×5} \)

= \(\frac{12}{15} + \frac{10}{15} \)

= \(\frac{22}{15} \)

(g) \(\frac{3}{4} - \frac{1}{3} \)

LCM of 4 and 3 = 12

\(\frac{3×3}{4×3} - \frac{1×4}{3×4} \)

= \(\frac{9}{12} - \frac{4}{12} \)

= \(\frac{5}{12} \)

(h) \(\frac{5}{6} - \frac{1}{3} \)

LCM of 6 and 3 = 6

\(\frac{5}{6} - \frac{1×2}{3×2} \)

= \(\frac{5}{6} - \frac{2}{6} \)

= \(\frac{3}{6} \) = \(\frac{1}{2} \)

(i) \(\frac{2}{3} + \frac{3}{4} + \frac{1}{2} \)

LCM of 3, 4 and 2 = 12

\(\frac{2×4}{3×4} + \frac{3×3}{4×3} + \frac{1×6}{2×6} \)

\(\frac{8}{12} + \frac{9}{12} + \frac{6}{12} \)

\(\frac{23}{12} \)

(j) \(\frac{1}{2} + \frac{1}{3} + \frac{1}{6} \)

LCM of 2, 3 and 6 = 6

\(\frac{1×3}{2×3} + \frac{1×2}{3×2} + \frac{1}{6} \)

\(\frac{3}{6} + \frac{2}{6} + \frac{1}{6} \)

\(\frac{6}{6} \) = 1

(k) \(1\frac{1}{3} + 3\frac{2}{3} \)

= \(\frac{4}{3} + \frac{11}{3} \)

= \(\frac{15}{3} \) = 5

(l) \(4\frac{2}{3} + 3\frac{1}{4} \)

= \(\frac{14}{3} + \frac{13}{4} \)

LCM of 3 and 4 = 12

\(\frac{14×4}{3×4} + \frac{13×3}{4×3} \)

= \(\frac{56}{12} + \frac{39}{12} \)

= \(\frac{95}{12} \) \)

(m) \(\frac{16}{5} - \frac{7}{5} \)

\(\frac{9}{5} \) = \(1\frac{4}{5} \)

(n) \(\frac{4}{3} - \frac{1}{2} \)

LCM of 3 and 2 = 6

\(\frac{4×2}{3×2} - \frac{1×3}{2×3} \)

= \(\frac{8}{6} - \frac{3}{6} \)

= \(\frac{5}{6} \) \)

- Q.2 Sarita bought \(\frac{2}{5} \) metre of ribbon and Lalita \(\frac{3}{4} \) metre of ribbon. What is the total length of the ribbon they bought?
- Q.3 Naina was given \(1\frac{1}{2} \) piece of cake and Najma was given \(1\frac{1}{3} \) piece of cake. Find the total amount of cake was given to both of them.
- Q. 4. Fill in the boxes: (a) \(\square - \frac{5}{8} = \frac{1}{4} \) (b) \(\square - \frac{1}{5} = \frac{1}{2} \) (c) \(\frac{1}{2} - \square = \frac{1}{6} \)
- Q.5 Complete the addition-subtraction box.
- Q6 A piece of wire \(\frac{7}{8} \) metre long broke into two pieces. One piece was \(\frac{1}{4} \) metre long. How long is the other piece?
- Q.7 Nandini’s house is \(\frac{9}{10} \) km from her school. She walked some distance and then took a bus for \(\frac{1}{2} \) km to reach the school. How far did she walk?
- Q.8 Asha and Samuel have bookshelves of the same size partly filled with books. Asha’s shelf is \(\frac{5}{6} \) th full and Samuel’s shelf is \(\frac{2}{5} \) th full. Whose bookshelf is more full? By what fraction?
- Q.9 Jaidev takes\(2\frac{1}{5} \) minutes to walk across the school ground. Rahul takes\(\frac{7}{4} \) minutes to do the same. Who takes less time and by what fraction?

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