Answer :

Time taken by Jaidev to walk across the school ground =\(2\frac{1}{5} \) = \(\frac{11}{5} \) minutes

Time taken by Rahul to walk across the school ground =
\(\frac{7}{4} \) minutes

\(\frac{11}{5} \) and \(\frac{7}{4} \)

By cross multiplication

11×4 and 5×7

44 > 35

\(\frac{11}{5} \) > \(\frac{7}{4} \)

\(\therefore \) Rahul takes less time than Jaidev to walk across the school ground

Difference = \(\frac{11}{5} \) - \(\frac{7}{4} \)

= \(\frac{11×4}{5×4} \) - \(\frac{7×5}{4×5} \)

= \(\frac{44}{20} \) - \(\frac{35}{20} \)

= \(\frac{9}{20} \)

- NCERT solutions for class 6 maths chapter 1 Knowing Our Numbers
- NCERT solutions for class 6 maths chapter 2 Whole Numbers
- NCERT solutions for class 6 maths chapter 3 Playing with Numbers
- NCERT solutions for class 6 maths chapter 4 Basic Geometrical Ideas
- NCERT solutions for class 6 maths chapter 5 Understanding Elementary Shapes
- NCERT solutions for class 6 maths chapter 6 Integers
- NCERT solutions for class 6 maths chapter 7 Fractions
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- NCERT solutions for class 6 maths chapter 11 Algebra
- NCERT solutions for class 6 maths chapter 12 Ratio and Proportion
- NCERT solutions for class 6 maths chapter 13 Symmetry
- NCERT solutions for class 6 maths chapter 14 Practical Geometry

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