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# Check of the following are solution of the equation x – 2y = 4 and which are not? i) (0, 2) ii) (2, 0) iii) (4, 0) iv) ($$\sqrt{2}$$, 4$$\sqrt{2}$$) v) (1, 1)

If (x, y) are the solutions of the equation x – 2y = 4 then, they satisfies that equation.

i) Let's put x = 0 and y = 2,
we get, L.H.S. = (0) - 2(2) = -4
so, since, L.H.S. $$\ne$$ R.H.S.
(0, 2) are not the solutions of given equation.

ii) Let's put x = 2 and y = 0,
we get, L.H.S. = (2) - 2(0) = 2
so, since, L.H.S. $$\ne$$ R.H.S.
(2, 0) are not the solutions of given equation.

iii) Let's put x = 4 and y = 0,
we get, L.H.S. = (4) - 2(0) = 4
so, since, L.H.S. = R.H.S.
(4, 0) are the solutions of given equation.

iv) Let's put x = $$\sqrt{2}$$ and y = 4$$\sqrt{2}$$,
we get, L.H.S. = ($$\sqrt{2}$$) - 2(4$$\sqrt{2}$$) = -7$$\sqrt{2}$$
so, since, L.H.S. $$\ne$$ R.H.S.
($$\sqrt{2}$$, 4$$\sqrt{2}$$) are not the solutions of given equation.

v) Let's put x = 1 and y = 1,
we get, L.H.S. = (1) - 2(1) = -1
so, since, L.H.S. $$\ne$$ R.H.S.
(1, 1) are not the solutions of given equation.