Answer :

(i) Construct \(\overline{AB} \) = 7.3 cm and \(\overline{CD} \) = 3.4 cm.

(ii) Take a point P on the given line l.

(iii) Construct \(\overline{PR} \) such that \(\overline{PR} \) = \(\overline{AB} \) = 7.3 cm.

(IV) Construct \(\overline{RQ} \) = \(\overline{CD} \) = 3.4 cm such that PQ = \(\overline{AB} \) – \(\overline{CD} \) .

Verification : On measuring, we observe that \(\overline{PQ} \) = 3.9 cm = 7.3 cm - 3.4 cm.
= \(\overline{AB} \) – \(\overline{CD} \)

Thus, \(\overline{PQ} \) = \(\overline{AB} \) – \(\overline{CD} \).

- Q.1 Draw a line segment of length 7.3 cm using a ruler.
- Q.2 Construct a line segment of length 5.6 cm using ruler and compasses.
- Q.3 Construct \(\overline{AB} \) of length 7.8 cm. From this, cut off \(\overline{AC} \) of length 4.7 cm. Measure \(\overline{BC} .\)
- Q.4 Given \(\overline{AB} \) of length 3.9 cm. Construct (\overline{PQ} \) such that the length of (\overline{PQ} \) is twice that of (\overline{AB} \) . Verify by measurement. (Hint : Construct \(\overline{PX} \) such that the length of \(\overline{PX} \) = length of \(\overline{AB} \) then cut off \(\overline{XQ} \) such that \(\overline{XQ} \) also has the length of \(\overline{AB} \) .

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