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Q. 6 Let ABC be a right triangle in which AB = 6 cm, BC = 8 cm and \(\angle \) B = 90°. BD is the perpendicular from B on AC. The circle through B, C, D is drawn. Construct the tangents from A to this circle.
Answer :

Steps of construction:
1. Dwar a right triangle ABC with AB = 6 cm, BC = 8 cm and \(\angle \) B = 90°
2. From B draw BD perpendicular to AC.
3. Draw perpendicular bisector of BC at point O'.
4. Take O' as a centre and OB as radius as radius, draw a circle passes through point B and C and D
5. Join O'A and draw perpendicular bisector O'A which intersect O'A.
6. Take that mid point centre, draw an arc on circle on point T.
7. Join AT, AT is required tengent.