ABC is a triangle. Locate a point in the interior of \(\triangle \) ABC which is equidistant from all the vertices of \(\triangle \)ABC.


Answer :

Circumcentre of a triangle is always equidistant from all the vertices of that triangle. Circumcentre is the point where perpendicular bisectors of all the sides of the triangle meet together.



In \(\triangle \)ABC, we can find the circumcentre by drawing the perpendicular bisectors of sides AB, BC, and CA of this triangle. O is the point where these bisectors are meeting together. Therefore, O is the point which is equidistant from all the vertices of \(\triangle \)ABC.

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