S and T are point on sides PR and QR of \(\triangle\) PQR such that \(\angle\) P = \(\angle\) RTS. Show that \(\triangle\) RPQ ~ \(\triangle\) RTS.

Given, S and T are point on sides PR and QR of \(\triangle\) PQR

And \(\angle\) P = \(\angle\) RTS.

In \(\triangle\) RPQ and \(\triangle\) RTS,
\(\angle\) RTS = \(\angle\) QPS (Given)
\(\angle\) R = \(\angle\) R (Common angle)
\(\triangle\) RPQ ~ \(\triangle\) RTS (AA similarity criterion)