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# S and T are point on sides PR and QR of $$\triangle$$ PQR such that $$\angle$$ P = $$\angle$$ RTS. Show that $$\triangle$$ RPQ ~ $$\triangle$$ RTS.

Given, S and T are point on sides PR and QR of $$\triangle$$ PQR
And $$\angle$$ P = $$\angle$$ RTS.
In $$\triangle$$ RPQ and $$\triangle$$ RTS,
$$\angle$$ RTS = $$\angle$$ QPS (Given)
$$\angle$$ R = $$\angle$$ R (Common angle)
$$\triangle$$ RPQ ~ $$\triangle$$ RTS (AA similarity criterion)