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Answer :

Given, \(\triangle\) ABE \({\displaystyle \cong }\) \(\triangle\) ACD.

AB = AC [By CPCT] ……………………………….(i)

And, AD = AE [By CPCT] ……………………………(ii)

In \(\triangle\) ADE and \(\triangle\) ABC, dividing eq.(ii) by eq(i),

AD/AB = AE/AC

\(\angle\) A = \(\angle\) A [Common angle]

\(\triangle\) ADE ~ \(\triangle\) ABC [SAS similarity criterion]

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