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Answer :
Given, ABC and AMP are two right triangles, right angled at B and M respectively.
(i) In \(\triangle\) ABC and \(\triangle\) AMP, we have,
\(\angle\) CAB = \(\angle\) MAP (common angles)
\(\angle\) ABC = \(\angle\) AMP = 90° (each 90°)
\(\triangle\) ABC ~ \(\triangle\) AMP (AA similarity criterion)
(ii) As, \(\triangle\) ABC ~ \(\triangle\) AMP (AA similarity criterion)
If two triangles are similar then the corresponding sides are always equal,
Hence, CA/PA = BC/MP