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Answer :
Given, initial velocity of train(u) = 0 m/s
{ As the train starts from rest}
final velocity(v) = 40 km h–1 = \( 40 \) ×\( 5 \over 18 \) = \( 11.11 \) m/s
Time taken(t) = 10 min \( = \ 10 × 60 \ = \ 600 \) s
So, a = \( v - u \over t \) = \( 11.11 - 0 \over 600 \) = \( 0.0185 \ m/s^2 \)