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# A train starting from a railway station and moving with uniform acceleration attains a speed 40 km h–1 in 10 minutes. Find its acceleration.

Given, initial velocity of train(u) = 0 m/s
{ As the train starts from rest}

final velocity(v) = 40 km h–1 = $$40$$ ×$$5 \over 18$$ = $$11.11$$ m/s

Time taken(t) = 10 min $$= \ 10 × 60 \ = \ 600$$ s

So, a = $$v - u \over t$$ = $$11.11 - 0 \over 600$$ = $$0.0185 \ m/s^2$$