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Answer :
Given, mass of the objects \( m_1 and m_2 \) = 1.5 kg
Initial velocity of the first object \( u_1 \) = 2.5 m/s
Initial velocity of the second object which is moving in the opposite direction \( u_2 \) = -2.5 m/s
When the two masses stick together, the resulting object has a mass of 3 kg i.e., \( m_1 + m_2 \)
Velocity of the resulting object (v) =?
By law of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision.
\(\Rightarrow \) (1.5) (2.5) + (1.5) (-2.5) = 0
Therefore, total momentum after collision = \( m_1 + m_2 \) v = (3) v = 0
This implies that the object formed after the collision has a velocity of 0 meters per second.