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Answer :
Given data:
Initial velocity u = 40 m/s
\( g = 10 m/s^2 \)
Max height final velocity = 0
We know that, \( v^2 = u^2 – 2 g s \)
[negative as the object goes up]
\( \Rightarrow 0 = (40)^2 – 2 x 10 x s \)
\( \Rightarrow s = \frac{(40 x 40)}{20} \)
Maximum height s = 80 m
Total Distance = s + s = 80 + 80
Total Distance = 160 m
Total displacement = 0 (The first point is the same as the last point)