Construct a \(\triangle{ABC}\) in which BC = 8 cm, \(\angle{B}\) = \(45^\circ\) and AB - AC = 35cm.

Given: In \(\triangle{ABC}\) in which BC = 8 cm, \(\angle{B}\) = \(45^\circ\) and AB - AC = 35cm.
Steps of construction:


1. Draw the base BC = 8cm

2. At the point B make an \(\angle{XBC}\) = \(45^\circ\).

3. Cut the line segment BD equal to AB - AC = 3.5 cm from the ray BX.

4. Join DC.

5. Draw the perpendicular bisector, say PQ of DC.

6. Let it intersect BX at a point A.

7. Join AC.
Hence, ABC is the required triangle.