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The paint in a certain container is suffcient to paint an area equal to 9.375 \({m}^2\). How many bricks of dimensions 22.5 cm × 10 cm × 7.5 cm can be painted out of this container?


Answer :

We know that,

Total surface area of one brick
= 2(lb + bh + lh)
= [2(22.5 X 10 + 10 x 7.5 + 22.5 x 7.5)] \({cm}^2\)
= [2(225 + 75 + 168.75)] \({cm}^2\)
= [2 x 468.75] \({cm}^2\)
= 937.5 \({cm}^2\)

Now, Let m bricks can be painted out by the paint of the container.

Thus, we get,

Area of m bricks = (m x 937.5) = 937.5m \({cm}^2\) ...(i)

Therefore, area that can be painted by the paint of the container = 9.375 \({m}^2\) ...(ii)
= 93750 \({cm}^2\)

Thus, equating (i) and (ii), we get,

93750 = 937.5m
\(\Rightarrow \) m = \(\frac{93750}{937.5}\)
\(\Rightarrow \) m = 100

Therefore, 100 bricks can be painted out by the paint of the container.

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