In a hot water heating system, there is a cylindrical pipe of length 28 m and diameter 5 cm. Find the total radiating surface in the system.

Given :
Height (h) of cylindrical pipe Length of cylindrical pipe = 28 m
Radius (r) of circular end of pipe
= \(\frac{5}{2}\) cm = 2.5 cm = 0.025 m

We know that,

CSA of cylindrical pipe
= \(2{\pi}rh\)
= \(2 × \frac{22}{7} × 0.025 × 28\) \({m}^2\)
= 4.4 \({m}^2\)

Therefore, the area of the radiating surface of the system is 4.4 \({m}^2\).