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# In a hot water heating system, there is a cylindrical pipe of length 28 m and diameter 5 cm. Find the total radiating surface in the system.

Given :
Height (h) of cylindrical pipe Length of cylindrical pipe = 28 m
Radius (r) of circular end of pipe
= $$\frac{5}{2}$$ cm = 2.5 cm = 0.025 m

We know that,

CSA of cylindrical pipe
= $$2{\pi}rh$$
= $$2 × \frac{22}{7} × 0.025 × 28$$ $${m}^2$$
= 4.4 $${m}^2$$

Therefore, the area of the radiating surface of the system is 4.4 $${m}^2$$.