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Answer :
The tin can will be cuboidal in shape while the plastic cylinder Hill be cylindrical in shape.
i)
Given :
Length (l) of tin can = 5 cm
Breadth (b) of tin can = 4 cm
Height (h) Of tin can = 15 cm
Therefore, Capacity of tin can
= l x b x h
= (5 x 4 x 15) \({cm}^{3}\)
= 300 \({cm}^{3}\)
ii)
Given :
Radius (r) of circular end of plastic cylinder = \(\frac{7}{2} cm = 3.5 cm\)
Height (h) of plastic cylinder = 10 cm
Therefore, Capacity of plastic cylinder
= \({\pi} {r}^2 h\)
\( = \frac{22}{7} × {3.5}^2 × 10\) \({cm}^{3}\)
= \(11 × 35\) \({cm}^{3}\)
= \(385\) \({cm}^{3}\)
Therefore, plastic cylinder has the greater capacity.
So, we get,
Difference in capacity
= (385 - 300) \({cm}^{3}\)
= 85 \({cm}^{3}\).