A soft drink is available in two packs –
i) a tin can with a rectangular base of length 5 cm and width 4 cm, having a height of 15 cm and
ii) a plastic cylinder with circular base of diameter 7 cm and height 10 cm. Which container has greater capacity and by how much?

The tin can will be cuboidal in shape while the plastic cylinder Hill be cylindrical in shape.

i)

Given :
Length (l) of tin can = 5 cm
Breadth (b) of tin can = 4 cm
Height (h) Of tin can = 15 cm

Therefore, Capacity of tin can
= l x b x h
= (5 x 4 x 15) \({cm}^{3}\)
= 300 \({cm}^{3}\)

ii)

Given :
Radius (r) of circular end of plastic cylinder = \(\frac{7}{2} cm = 3.5 cm\)
Height (h) of plastic cylinder = 10 cm

Therefore, Capacity of plastic cylinder
= \({\pi} {r}^2 h\)
\( = \frac{22}{7} × {3.5}^2 × 10\) \({cm}^{3}\)
= \(11 × 35\) \({cm}^{3}\)
= \(385\) \({cm}^{3}\)

Therefore, plastic cylinder has the greater capacity.
So, we get,

Difference in capacity
= (385 - 300) \({cm}^{3}\)
= 85 \({cm}^{3}\).